Problem
Given an array nums. We define a running sum of an array as runningSum[i] = sum(nums[0]…nums[i]).
Return the running sum of nums.
Solution
var runningSum = function(nums) {
let result = new Array();
if(nums.length > 1){
for(let i =0; i< nums.length; i++){
let rsum = 0;
for(let j = 0; j<(i+1); j++){
rsum = rsum+nums[j];
}
result.push(rsum);
}
}
return result;
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